SOLUTION: Graph f(x)=5x-x³ -x⁵ This is as far as I get, but I think I'm setting it up wrong: -x(x⁴+x² - 5)=0

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Question 956309: Graph f(x)=5x-x³ -x⁵
This is as far as I get, but I think I'm setting it up wrong:
-x(x⁴+x² - 5)=0
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Graph f(x)=5x-x³ -x⁵
This is as far as I get, but I think I'm setting it up wrong:
-x(x⁴+x² - 5)=0
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Do you want to graph it or solve it?
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5x+-+x%5E3+-+x%5E5+=+0
-x%28x%5E4+%2B+x%5E2+-+5%29+=+0
x = 0 is one solution.
x%5E4+%2B+x%5E2+-+5+=+0
Sub u for x^2
u%5E2+%2B+u+-+5+=+0
Now it's a quadratic, solve for u.
Sub back x^2 for u, etc.
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To graph it, pick values for x and find f(x), as always.
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dl the FREE graph software at
http://www.padowan.dk