SOLUTION: A projectile is fired straight upward from the ground with an initial speed of 96 feet per second, then its height h after t seconds is given by the equation
h(t) = -16t2 + 96t
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-> SOLUTION: A projectile is fired straight upward from the ground with an initial speed of 96 feet per second, then its height h after t seconds is given by the equation
h(t) = -16t2 + 96t
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Question 953082: A projectile is fired straight upward from the ground with an initial speed of 96 feet per second, then its height h after t seconds is given by the equation
h(t) = -16t2 + 96t
Find the maximum height of the projectile. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A projectile is fired straight upward from the ground with an initial speed of 96 feet per second, then its height h after t seconds is given by the equation
h(t) = -16t^2 + 96t
Max is the vertex of the parabola, at t = -b/2a
t = -96/-32 = 3 seconds
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h(3) = -16*9 + 96*3 = 144 feet
