SOLUTION: Find the vertex for the parabola given below. f(x) = 3x² + 12x + 16
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Question 953080
:
Find the vertex for the parabola given below.
f(x) = 3x² + 12x + 16
Answer by
Alan3354(69443)
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Here's a similar problem:
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The vertex of y = -3x²- 6x - 9 lies in which quadrant?
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vertex at x = -b/2a = 6/-6 = -1
y(-1) = -3 + 6 - 9 = -6
--> (-1,-6) in Q3