SOLUTION: Solve the system using substitution. y = 4x - 3 y = 5x - 1 A. (9, -4) B. (5, -1) C. (4, -3) D. (-2, -11)

Algebra ->  Graphs -> SOLUTION: Solve the system using substitution. y = 4x - 3 y = 5x - 1 A. (9, -4) B. (5, -1) C. (4, -3) D. (-2, -11)       Log On


   

Question 947987: Solve the system using substitution.

y = 4x - 3
y = 5x - 1

A. (9, -4)
B. (5, -1)
C. (4, -3)
D. (-2, -11)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

y+=+4x+-3.......eq.1
y+=+5x+-1.......eq.2
------------------------------substitute 5x+-1 for y in eq.1

5x+-1+=+4x+-3.......eq.1...solve for x
5x+-4x+=+1+-3
highlight%28x+=+-2%29
go to y+=+5x+-1.......eq.2 substitute -2 for x and solve for y
y+=+5%28-2%29+-1
y+=+-10+-1
highlight%28y+=+-11%29
solution is:
D. (-2, -11)