SOLUTION: How would I go about figuring the graphs of these two functions: H(x)=4 - |2x-6| and G(t)= 1/2(t^2 - 4t) Please help I need to know where it crosses the x and y axis a

Algebra ->  Graphs -> SOLUTION: How would I go about figuring the graphs of these two functions: H(x)=4 - |2x-6| and G(t)= 1/2(t^2 - 4t) Please help I need to know where it crosses the x and y axis a      Log On


   



Question 947660: How would I go about figuring the graphs of these two functions:
H(x)=4 - |2x-6|
and
G(t)= 1/2(t^2 - 4t)
Please help I need to know where it crosses the x and y axis and why.
Thank you

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
One would expect you mean G%28t%29=+%281%2F2%29%28t%5E2+-+4t%29
factorable and the zeros easily identified.
%281%2F2%29t%28t-4%29.
Zeros for t=0 and t=4.
y-intercept for t=0.


The absolute value function H has two parts, the critical value of x being 3.
H%28x%29=4-2abs%28x-3%29
-
H(x)=4-2(3-x) for x<3
and
H(x)=4-2(x-3) for x>=3

Simplifying this,
H%28x%29=2x-2 for x%3C3
and
H%28x%29=-2x%2B10 for x%3E=3

Graph for H(x):
graph%28300%2C300%2C-6%2C6%2C-6%2C6%2C4-2%2Aabs%28x-3%29%29