Question 929903: Find the equation of a parabola with a vertex of (9,-6) and a point of (2,5)
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex and x = h is the Line of Symmetry ,
the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)
..........
parabola with a vertex of (9,-6) and a point of (2,5)
y = a(x-9)^2 - 6
5 = a(-7)^2 - 6
11/49 = a
y = (11/49)(x-9)^2 - 6
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