Question 929201: 8. find the equation of the the line passing thru (4,-6) and (-3,5)
9. find the equation of the line with a slope of 0 and passing through the point (8,-6)
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! (4,-6) and (-3,5)
slope = m = dy/dx
m = (5+6)/(-3-4)
m = (-11/7)
y - 5 = (-11/7)(x + 3)
y = (-11/7)x + 3*(-11/7) + 5
y = (-11/7)x - 33/7 + 35/7
y = (-11/7)x + 2/7
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(8,-6)
slope = 0 = horizontal line
y = -6
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