SOLUTION: How do I figure out the graph for: f(x) = 3(2^x)-6 I know that x=-6 is the horizontal asymptote when I go to make a t-table my points are all over the place and not consisten

Algebra ->  Graphs -> SOLUTION: How do I figure out the graph for: f(x) = 3(2^x)-6 I know that x=-6 is the horizontal asymptote when I go to make a t-table my points are all over the place and not consisten      Log On


   

Question 917221: How do I figure out the graph for: f(x) = 3(2^x)-6
I know that x=-6 is the horizontal asymptote
when I go to make a t-table my points are all over the place and not consistent.
like plugging in x=1 results in 0. x=2 results in 6...
What is the proper way to figure out this graph?
Thank you
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The factor 3, just stretches the graph vertically. The minus 6 moves the graph downward by 6 units.

Work with easy values to help get good points to sketch the graph.

x____________f(x)
-2_________3%282%5E%28-2%29%29-6=3%2F4-6=-5%261%2F4
-1_________3%282%5E%28-1%29%29-6=3%2F2-6=-4%261%2F2
0__________3%282%5E0%29-6=3
1__________3%2A2-6=0
2__________3%2A2%5E2-6=6


graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C3%2A2%5Ex-6%29

For comparison this is 2^x:
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C2%5Ex%29