SOLUTION: Hi I need help on this question please: Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form y=mx+b.

Algebra ->  Graphs -> SOLUTION: Hi I need help on this question please: Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form y=mx+b.       Log On


   

Question 901720: Hi I need help on this question please:
Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form y=mx+b.
(3,4) 7x+y=12
I answered: y=1/7x+1
I just want to know if I'm right and If I'm wrong, will you please let me know how to solve the problem. Thanks a lot.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

the standard slope-intercept form for an equation of a line is 

y+=+highlight_green%28m%29x+%2B+highlight%28b%29  where m is the slope and b the y-intercept.  

7x+y=12 0r y = -7x + 12, m = -7

New Perpendicular Line: m = (1/7)(negative reciprocal)   -7%281%2F7%29+=+-1

***Using point-slope form, y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29 P(3,4)

y - 4 = (1/7)(x-3)

y - 4  = (1/7)x -3/7

y - 4  = (1/7)x -3/7 + 28/7

y = (1/7)x + 25/7   +28%2F7+-+3%2F7+=+25%2F3

0r x - 7y = -25  In Standard Form