SOLUTION: Find the value of k so that the line through the points (-2,3) and (6,k) has y-intercept 6.

Algebra ->  Graphs -> SOLUTION: Find the value of k so that the line through the points (-2,3) and (6,k) has y-intercept 6.      Log On


   



Question 901405: Find the value of k so that the line through the points (-2,3) and (6,k) has y-intercept 6.
Answer by lwsshak3(11628) About Me  (Show Source):
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Find the value of k so that the line through the points (-2,3) and (6,k) has y-intercept 6.
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Standard form of equation for a line: y=mx+b, m=slope, b=y-intercept
For given problem:
slope, m=∆y/∆x=(k-3)/(6-(-2))=(k-3)/8
y=mx+6
using coordinates of given point (-2,3)
3=m*-2+6
2m=3
m=3/2
..
%28k-3%29%2F8=3%2F2
2(k-3)=8*3
2k-6=24
2k=30
k=15