SOLUTION: Draw the graph of this equation:y=1/3x-3

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Question 90130: Draw the graph of this equation:y=1/3x-3
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Graphing Linear Equations
In order to graph y=%281%2F3%29%2Ax-3 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-9

y=%281%2F3%29%2A%28-9%29-3

y=-9%2F3-3 Multiply

y=-18%2F3 Add

y=-6 Reduce

So here's one point (-9,-6)




Now lets find another point

Plug in x=-6

y=%281%2F3%29%2A%28-6%29-3

y=-6%2F3-3 Multiply

y=-15%2F3 Add

y=-5 Reduce

So here's another point (-6,-5). Add this to our graph





Now draw a line through these points

So this is the graph of y=%281%2F3%29%2Ax-3 through the points (-9,-6) and (-6,-5)


So from the graph we can see that the slope is 1%2F3 (which tells us that in order to go from point to point we have to start at one point and go up 1 units and to the right 3 units to get to the next point) the y-intercept is (0,-3)and the x-intercept is (9,0)


We could graph this equation another way. Since b=-3 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,-3).


So we have one point (0,-3)





Now since the slope is 1%2F3, this means that in order to go from point to point we can use the slope to do so. So starting at (0,-3), we can go up 1 units



and to the right 3 units to get to our next point


Now draw a line through those points to graph y=%281%2F3%29%2Ax-3


So this is the graph of y=%281%2F3%29%2Ax-3 through the points (0,-3) and (3,-2)