SOLUTION: Find the area under the curve for the function f(x)= 4x^3+3x^2-x+1 on the interval [1,2].

Algebra ->  Graphs -> SOLUTION: Find the area under the curve for the function f(x)= 4x^3+3x^2-x+1 on the interval [1,2].      Log On


   

Question 880409: Find the area under the curve for the function f(x)= 4x^3+3x^2-x+1 on the interval [1,2].
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the area under the curve for the function f(x)= 4x^3+3x^2-x+1 on the interval [1,2].
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f%28x%29=+4x%5E3%2B3x%5E2-x%2B1
INT+=+F%28x%29+=+x%5E4+%2B+x%5E3+-+x%5E2%2F2+%2B+x+%2B+C
Area = F(2) - F(1)

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

Area under curve:  

int%28+4x%5E3%2B3x%5E2-x%2B1%2C+dx%2C+1%2C+2%29

g(x) = x^4 + x^3 -x^2/2 + x from 1 to 2

Area under curve: g(2) - g(1) = 24 - 2.5 = 21.5