SOLUTION: Can you find the vertical asymptote, horizontal asymptote, and the graph of: f(x)=2x/x^2-1 Please answer it clearly 'cause I'm only a high school student. Thanks in advance.

Algebra ->  Graphs -> SOLUTION: Can you find the vertical asymptote, horizontal asymptote, and the graph of: f(x)=2x/x^2-1 Please answer it clearly 'cause I'm only a high school student. Thanks in advance.       Log On


   



Question 865161: Can you find the vertical asymptote, horizontal asymptote, and the graph of:
f(x)=2x/x^2-1
Please answer it clearly 'cause I'm only a high school student. Thanks in advance. Please answer ASAP.

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = 2x /(x^2-1)
we find vertical asymptotes by setting the denominator to 0
x^2-1 = 0
x^2 = 1
vertical asymptotes at x = 1 and -1
horizontal asymptote is found by therm with highest power in the numerator and denominator, in our case they are 2x/x^2, note that the exponent in the denominator is greater than the numerator, this tells us that the horizonatal asymptote is y = 0 which is the x axis
here is the graph
+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+2x%2F%28x%5E2-1%29+%29+