SOLUTION: One line passes through the points (−12,16) and (−1,38). A second line has the equation 2y+x=23. Are these lines parallel, perpendicular, or neither?

Algebra ->  Graphs -> SOLUTION: One line passes through the points (−12,16) and (−1,38). A second line has the equation 2y+x=23. Are these lines parallel, perpendicular, or neither?       Log On


   



Question 858086: One line passes through the points (−12,16) and (−1,38). A second line has the equation 2y+x=23. Are these lines parallel, perpendicular, or neither?
Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope of the line through (-12,16) (-1,38)
Set x1 = -12 , y1 = 16 , x2 = -1 , y2 = 38
in the equation slope = %28y2+-+y1%29%2F%28x2-x1%29
%2838+-+16%29%2F%28+-1+-+%28-12%29%29 =
22/11 = 2
So the slope is 2
Now find the slope for 2y+x=23
add -x to each side
2y = -x + 23
divide each side by 2
y = (-1/2)x + 23/2
So the slope is -1/2
Since this slope is the negative inverse of 2 we
have perpendicular lines. %282%29%2A%28-1%2F2%29 = -1