SOLUTION: Sketch the parabola {{{y=x^2+x-6}}} by using its intercepts Please show all steps

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Question 851070: Sketch the parabola y=x%5E2%2Bx-6 by using its intercepts
Please show all steps
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The leading term tells you the graph opens upward and so vertex is a minimum, and you should find the quadratic factorable.
y=x%5E2%2Bx-6=%28x-2%29%28x%2B3%29
zeros are x=2 and x=-3.
y is negative between x= 2 and x=-3, but positive outside that interval.
The axis of symmetry is x=%282%2B%28-3%29%29%2F2=-1%2F2

graph%28300%2C300%2C-10%2C10%2C-13%2C13%2Cx%5E2%2Bx-6%29