SOLUTION: graph the following function and state its domain and range; f(x)=x^2-4

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Question 849758: graph the following function and state its domain and range; f(x)=x^2-4
Answer by lwsshak3(11628) About Me  (Show Source):
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graph the following function and state its domain and range; f(x)=x^2-4
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This is an equation of a parabola that opens up with vertex at the origin.
Its standard (vertex) form of equation:y=A(x-h)^2+k, (h,k)=vertex
A>0, parabola opens up
A<0, parabola opens down
For given parabola:
vertex: (0,-4)
x-intercepts:
set y=0
x^2-4=0
(x+2)(x-2)=0
x=±2
domain: (-∞,∞)
range: [-4,∞)
see graph below:
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2Cx%5E2-4%29+