SOLUTION: Find the distance between the points of intersection of the graphs y = x^2 + 1 and y = 5. Help?

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Question 835364: Find the distance between the points of intersection of the graphs
y = x^2 + 1 and y = 5. Help?

Found 2 solutions by reviewermath, josgarithmetic:
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
Q:
Find the distance between the points of intersection of the graphs
y+=+x%5E2+%2B+1 and y = 5
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A:
To get the points of intersection, we solve
x%5E2+%2B+1+=+5 then solve for x
x%5E2+=+4
x = ±2
The points of intersection are (2, 5) and (-2, 5).
The y-coordinates are the same so we just compute the absolute value of the difference between the x-coordinates to get the distance between the two points.
distance = |2 - (-2)| = highlight%284%29
Here's the graph:
+graph%28+400%2C+400%2C+-6%2C+5%2C+-5%2C+10%2C+x%5E2%2B1%2C+5%29+

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
First find the points of intersection. Second, you would not need the Distance Formula, because these two equations and their graphs allow you to use symmetry of the shapes.

y=x%5E2%2B1=5
x%5E2=5-1=4
x=-2 and x=2 for x coordinates for intersections.

POINTS OF INTERSECTION: (-2,5), and (2,5)

Note that the symmetry axis for the parabola is the line x=0. The y value is y=5, which you can simply treat as a horizontal number line, because, really that is what is y=5. The distance between x=-2 and x=2 is highlight%284%29.


graph%28300%2C300%2C-4%2C4%2C-1%2C8%2Cx%5E2%2B1%2C5%29