SOLUTION: Solve 6x-0.37=5(x-0.28) The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm,find the length

Algebra ->  Graphs -> SOLUTION: Solve 6x-0.37=5(x-0.28) The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm,find the length      Log On


   

Question 83138: Solve 6x-0.37=5(x-0.28)
The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm,find the length of one of the equal legs.
solve 2/5x=-10
solve 4x+8=-4.
I appreciate whatever help i can get on these. thank you so much.
Answer by Mona27(45) About Me  (Show Source):
You can put this solution on YOUR website!
1) 6x-0.37=5%28x-0.28%29
First you need to multiply out the bracket. Multiply 5 into each of the two terms you have:
6x-0.37=5x-1.4
Then rearrange to get all terms in x on one side and everything else on the other (don't forget to change the signs when you move the terms across the "equal" sign!!):
6x-5x=0.37-1.4
x=-1.03
2) When dealing with word problems, just follow what the question is saying, word for word:
"The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base."
Length of an equal leg = L
4 times the length of the base = 4b
L=4b-8
"If the perimeter is 29 cm,find the length of one of the equal legs."
The perimeter is the sum of all sides:
29=2L%2Bb
Substituting from the first equation into the second (replacing L with 4b-8):
29=2%284b-8%29%2Bb
29=8b-16%2Bb
Rearrange:
8b%2Bb=29%2B16
9b=45
giving b=5
and hence L=4%285%29-8=12
3) solve %282%2F5%29x=-10
Here you can multiply both sides by 5 to get rid of the fraction:
2x=-50
And then divide by 2 to isolate x:
x=-25
4)solve 4x+8=-4
I guess this one should be easy now, right?
4x=-12
x=-3