SOLUTION: What is the slope of the line tangent to the curve at a given value of x? f(x)= 8x^2 + 5x at x= 3

Algebra ->  Graphs -> SOLUTION: What is the slope of the line tangent to the curve at a given value of x? f(x)= 8x^2 + 5x at x= 3      Log On


   

Question 828628: What is the slope of the line tangent to the curve at a given value of x?
f(x)= 8x^2 + 5x at x= 3
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
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differentiate f(x):
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f'(x) = 8*2x + 5
f'(x) = 16x + 5
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at x=3
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f'(3) = 16*3 + 5
f'(3) = 53
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answer:
the slope of the tangent at x=3 is: 53
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