SOLUTION: Finding the slope of a line* M=Y2 - Y1 --------- X2 - X1 A= 2,6 D= -3,-3 Please show how to get the answer.

Algebra ->  Graphs -> SOLUTION: Finding the slope of a line* M=Y2 - Y1 --------- X2 - X1 A= 2,6 D= -3,-3 Please show how to get the answer.      Log On


   



Question 82663: Finding the slope of a line*
M=Y2 - Y1
---------
X2 - X1

A= 2,6
D= -3,-3 Please show how to get the answer.

Found 2 solutions by jim_thompson5910, josmiceli:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Finding the slope


Slope of the line through the points (2, 6) and (-3, -3)



m+=+%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29


m+=+%28-3+-+6%29%2F%28-3+-+2%29


m+=+%28-9%29%2F%28-5%29


m+=+9%2F5



Answer: Slope is m+=+9%2F5


Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
m+=+%28y%5B2%5D+-+y%5B1%5D%29+%2F+%28x%5B2%5D+-+x%5B1%5D%29
A = (2,6)
D = (-3, -3)
This is just a matter of getting the subscripts right (the 1's and 2's)
The given points are going to end up being (x%5B1%5D),(y%5B1%5D)
and (x%5B2%5D),(y%5B2%5D).
You decide and either way it works.
A = (x%5B1%5D),(y%5B1%5D)
D = (x%5B2%5D),(y%5B2%5D)
That will work fine, and also
A = (x%5B2%5D),(y%5B2%5D)
D = (x%5B1%5D),(y%5B1%5D)
That works fine, too
I'll do it both ways to prove it
A = (2,6)
(2,6) = (x%5B1%5D),(y%5B1%5D)
D = (-3, -3)
(-3, -3) = (x%5B2%5D),(y%5B2%5D)
m+=+%28y%5B2%5D+-+y%5B1%5D%29+%2F+%28x%5B2%5D+-+x%5B1%5D%29
m+=+%28-3+-+6%29+%2F+%28-3+-+2%29
m+=+%28-9%29+%2F+%28-5%29
m+=+9%2F5
-----------------------------
Now the other way
A = (2,6)
(2,6) = (x%5B2%5D),(y%5B2%5D)
d = (-3, -3)
(-3, -3) = (x%5B1%5D),(y%5B1%5D)
m+=+%28y%5B2%5D+-+y%5B1%5D%29+%2F+%28x%5B2%5D+-+x%5B1%5D%29
m+=+%286+-+%28-3%29%29+%2F+%282+-+%28-3%29%29
m+=+%286+%2B+3%29+%2F+%282+%2B+3%29
m+=+9%2F5
So, you can't go wrong as long as you keep
straight which point is which. Hope this helps