SOLUTION: (x+6)^2+(y+3)^2=4 ellipse

Algebra ->  Graphs -> SOLUTION: (x+6)^2+(y+3)^2=4 ellipse      Log On


   



Question 822227: (x+6)^2+(y+3)^2=4
ellipse

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
(x+6)˛+(y+3)˛=4

You say that's an ellipse.  It's actually a circle with center (-6,-3),
and radius 2. However it is true that a circle is a special case of 
an ellipse when both foci and the center coincide, and the major and 
minor axes are equal:

It is in the circle form

(x-h)˛+(y-k)˛=r˛ with center (h,k)=(-6,-3) and radius˛ = r˛=4, so r=2.

If we divide it through by 4, we have

%28x%2B6%29%5E2%2F4%22%22%2B%22%22%28y%2B3%29%5E2%2F4 %22%22=%22%22 1

which is in the form of an ellipse:

%28x-h%29%5E2%2Fa%5E2%22%22%2B%22%22%28y-k%29%5E2%2Fb%5E2 %22%22=%22%22 1

where the center = (-6,-3), semi-major axis = a = b = semi-minor-axis = 2,
both the same as the radius:



Edwin