You can put this solution on YOUR website! :
can someone please help me solve this rational equation b+3/b+b+4/b+5=15/Bsquared+5b
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The way it's written is ambiguous, a few brackets would help alot
I assume you mean:
: =
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Factor out b in the last denominator: =
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It becomes obvious that the common denominator is b(b+5), mult each term by that, then you have:
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(b+5)(b+3) + b(b+4) = 15
(:
b^2 + 8b + 15) + (b^2 + 4b) = 15; FOIL and mult what's inside the brackets
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b^2 + b^2 + 8b + 4b + 15 - 15 = 0; group like terms on the left
:
2b^2 + 12b = 0
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2b(b + 6) = 0; factor out 2b
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two solutions:
b = 0; cannot be a solution (0 in the denominator)
and
b = -6
:
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Check b = -6 in the original equation =
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I'll let you do the math here, and see that equality reigns.
