SOLUTION: write the equasion of the line which passes through point (2,1) and is parallel to the line with equasion y=5/2x+6
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Question 80022: write the equasion of the line which passes through point (2,1) and is parallel to the line with equasion y=5/2x+6 Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! A PARALLEL LINE NEEDS TO HAVE THE SAME SLOPE. THUS THE SLOPE IS 5/2. NOW SUBSTITUTE (2,1) FOR X & Y IN THE QUADRATIC EQUATION Y=mX+b
1=5/2*2+b
1=5+b
b=1-5
b=-4 Y INTERCEPT.
THEREFORE THE EQUATION OF THIS PARALLEL LINE PASSING THRU (2,1) IS
Y=5/2X-4
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