SOLUTION: What is the x-intercept of y=square root x^2+9?
I squared both sides and ended up with 0=x^2+9
subtracted 9 from both sides .... -9=x^2
Since a negative doesn't go under a r
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-> SOLUTION: What is the x-intercept of y=square root x^2+9?
I squared both sides and ended up with 0=x^2+9
subtracted 9 from both sides .... -9=x^2
Since a negative doesn't go under a r
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Question 795475: What is the x-intercept of y=square root x^2+9?
I squared both sides and ended up with 0=x^2+9
subtracted 9 from both sides .... -9=x^2
Since a negative doesn't go under a radical, do I divide by -1? And if I divide by -1 what do I do with -x^2? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! What is the x-intercept of y=square root x^2+9?
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Let y = 0
Then sqrt(x^2+9) = 0
Then x^2+9 = 0
x^2 = -9
x = +-3i
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There is no x-intercept.
Cheers,
Stan H.
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