SOLUTION: Write the equation of a line parallel to the given line but passing through the given point.
y=-1/2x+1 (4,2)
Then write the equation of a line perpendicular to the given line but
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-> SOLUTION: Write the equation of a line parallel to the given line but passing through the given point.
y=-1/2x+1 (4,2)
Then write the equation of a line perpendicular to the given line but
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Question 792381: Write the equation of a line parallel to the given line but passing through the given point.
y=-1/2x+1 (4,2)
Then write the equation of a line perpendicular to the given line but passing through the given point.
Y=-3x-6; (-1,5)
*I believe I have the second part complete. I got the answer y=3x+5, but I cannot figure out the top equation to save my life. please and thank you.
You can put this solution on YOUR website! Write the equation of a line parallel to the given line but passing through the given point.
y=-1/2x+1 (4,2)
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The slope of y=-1/2x+1 is m = -1/2 since the equation y=-1/2x+1 is in the form y = mx+b where m = -1/2 (slope) and b = 1 (y-intercept)
The slope of ANY line parallel to this one will also be -1/2, so m is still -1/2.
y = mx + b
y = (-1/2)x + b ... plug in the parallel slope
2 = (-1/2)(4) + b ... plug in the given point (4,2)
2 = (-1/2)(4/1) + b
2 = (-1*4)/(2*1) + b
2 = (-4)/(2) + b
2 = -2 + b
2 + 2 = b
4 = b
b = 4
Therefore, the slope is m = -1/2 and the y-intercept is b = 4
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