SOLUTION: I am totally lost on how to do this. Any help would be appreciated:) Write an equation for a linear function whose graph has the given characteristics. Passes through (&#87

Algebra ->  Graphs -> SOLUTION: I am totally lost on how to do this. Any help would be appreciated:) Write an equation for a linear function whose graph has the given characteristics. Passes through (&#87      Log On


   

Question 790830: I am totally lost on how to do this. Any help would be appreciated:)


Write an equation for a linear function whose graph has the given characteristics.
Passes through (−2, 8) and (2, −10)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Use the general point-slope formula
You are given:
( x1,y1) = ( -2,8 )
(x2,y2) = ( 2, -10 )
-----------------
( y2 - y1 ) / ( x2 - x1 ) = ( y - y1 ) / ( x - x1 )
+%28+-10+-+8+%29+%2F+%28+2+-%28-2%29+%29+=+%28+y+-+8+%29+%2F+%28+x+-%28-2%29+%29+
+-18+%2F+4+=+%28+y+-+8+%29+%2F+%28+x+%2B+2+%29+
Multiply both sides by +4%2A%28+x%2B2+%29+
+-18%2A%28+x%2B2+%29+=+4%2A%28+y+-+8+%29+
+-9%2A%28+x%2B2+%29+=+2%2A%28+y+-+8+%29+
+-9x+-+18+=+2y+-+16+
+2y+=+-9x+-+2+
+y+=+%28-9%2F2%29%2Ax+-+1+
-------------------
check for given points:
(-2,8)
+8+=+%28-9%2F2%29%2A%28-2%29+-+1+
+8+=+9+-+1+
+8+=+8+
and
(2,-10)
+-10+=+%28-9%2F2%29%2A2+-+1+
+-10+=+-9+-+1+
+-10+=+-10+
OK