SOLUTION: How do I write the equation of the line with slope -5 and y-intercept (0, 5)?

Algebra ->  Graphs -> SOLUTION: How do I write the equation of the line with slope -5 and y-intercept (0, 5)?      Log On


   



Question 78906: How do I write the equation of the line with slope -5 and y-intercept (0, 5)?
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
You can do this directly. Use the slope intercept form of an equation. This form is:
.
y+=+mx+%2B+b
.
where m is the slope and b is the value of y where the graph crosses the y-axis.
.
The problem tells you that the slope (m) is -5. Substitute this into the slope intercept
form and you get:
.
y+=+-5x+%2B+b
.
and the problem also tells you that the point (0, 5) is the y-intercept. At that point
the value of y is 5. Substitute this for b in the slope intercept equation and you get:
.
y+=+-5x+%2B+5
.
That's the answer. This equation is one that has a graph with a slope of -5 and crosses
the y-axis at +5.
.
Hope this helps you to understand the slope intercept form of an equation.