Question 766973: y=(x+4)^2+3
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! Graph:
y=(x+4)^2+3
by using techniques of "transformations".
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Starting point:
y = x^2
This is simply a parabola that opens upwards and the vertex is at the origin.
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y = (x+4)^2
The above "horizontally shifts" the "starting point" to the LEFT 4 units. That is, the vertex is now at (-4,0).
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Finally,
y = (x+4)^2 + 3
Shifts it vertically UP three units. That is, the vertex is now at (-4,3).
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