Question 75633: find the slope and y-intercept of the line which is the graph of the equation
2y=5(x+1)
Found 2 solutions by checkley75, bucky:
Answer by checkley75(3666)   (Show Source):
You can put this solution on YOUR website! 2Y=5(X+1)
2Y=5X+5
Y=5X/2+5/2 THE SLOPE OF THIS LINE IS (5/2) & THE Y INTERCEPT IS (0,5/2)
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 5x/2 +5/2).
Answer by bucky(2189) (Show Source):
You can put this solution on YOUR website! If you can "rework" the equation into the form y = mx + b, then you will be able to identify the
slope and the y-intercept. The slope is m, the multiplier of x, and the y-intercept
is b, the constant that follows the x term. So let's work on the equation. You are given:
.
2y=5(x+1)
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Multiply out the right side and the equation becomes:
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2y = 5x + 5
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Close to what we need, but we need the solution for y ... not for 2y. So let's divide
every term on both sides by 2. When we do, we get:
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y = (5/2)*x + 5/2
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This is exactly in the form y = mx + b which is called the slope-intercept form.
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By comparing our equation with the slope-intercept form, we can see that m, the multiplier
of x is (5/2). And m is the slope. So the slope is (5/2). Then by comparing again we
see that b is the constant on the right side. So b, which is the y-intercept, is also
5/2. So the slope is 5/2 and so is the y-intercept.
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Hope this helps you become more familiar with the slope-intercept form of linear equations.
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