SOLUTION: Please help. What am I doing here? In exercise 2, evaluate each function for the value specified. f(x)=x^2-7x +10; find (a) f(0), (b) f(5), and (c) f(-2).

Algebra ->  Graphs -> SOLUTION: Please help. What am I doing here? In exercise 2, evaluate each function for the value specified. f(x)=x^2-7x +10; find (a) f(0), (b) f(5), and (c) f(-2).       Log On


   



Question 74080: Please help. What am I doing here?
In exercise 2, evaluate each function for the value specified.
f(x)=x^2-7x +10; find (a) f(0), (b) f(5), and (c) f(-2).

Found 2 solutions by jim_thompson5910, bucky:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
a)
f%28x%29=x%5E2-7x+%2B10
f%280%29=%280%29%5E2-7%280%29+%2B10When you evaluate f(0) just plug in 0 in for every x.
f%280%29=10

b)
f%28x%29=x%5E2-7x+%2B10
f%285%29=5%5E2-7%285%29+%2B10When you evaluate f(5) just plug in 0 in for every x.
f%285%29=25-35+%2B10
f%285%29=-10+%2B10
f%285%29=0

c)
f%28x%29=x%5E2-7x+%2B10
f%28-2%29=%28-2%29%5E2-7%28-2%29+%2B10When you evaluate f(-2) just plug in 0 in for every x.
f%28-2%29=4-%28-14%29+%2B10
f%28-2%29=4%2B14+%2B10
f%28-2%29=28

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
f%28x%29=x%5E2-7x+%2B10
Find: (a) f(0), (b) f(5), and (c) f(-2)
.
All this problem require you to do is assign values to x and solve for the given function.
.
In (a) f(0) means go to the given function and substitute 0 for every x you find. When you
do that the function is:
.
f%280%29=0%5E2-7%2A0+%2B10 and this simplifies it to f%280%29+=+0+%2B+0+%2B10 which reduces to:
.
f%280%29+=+%2B10
.
In (b) f(5) means go to the given function and replace all the x's in it with 5. When you do
it becomes: f%285%29+=+5%5E2+-+7%2A5+%2B+10+=+25+-+35+%2B+10 which reduces to:
.
f%280%29+=+25+-35+%2B+10+=+0 so that f%285%29+=+0
.
In (c) f%28-2%29+=+%28-2%29%5E2+-7%2A%28-2%29+%2B+10 which becomes f%28-2%29=+4+%2B+14+%2B10 and this
simplifies to f%28-2%29+=+28
.
Hope this helps you to understand the problem.