SOLUTION: Can someone help me with this please??? Write the slope intercept form of the line that pass through point A(-5,9) and is perpendicular to the line with equation 2y-3x+5=0

Algebra ->  Graphs -> SOLUTION: Can someone help me with this please??? Write the slope intercept form of the line that pass through point A(-5,9) and is perpendicular to the line with equation 2y-3x+5=0      Log On


   

Question 730119: Can someone help me with this please???
Write the slope intercept form of the line that pass through point A(-5,9) and is perpendicular to the line with equation 2y-3x+5=0
Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Write the slope intercept form of the line that pass through point A(-5,9) and is perpendicular to the line with equation 2y-3x+5=0
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Find the slope of the line, m1
2y-3x+5=0
Put it into slope-intercept form (solve for y)
y = (3/2)x - 5/2
m1 = 3/2
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The slope of lines perpendicular is the negative inverse = -2/3
m = -2/3
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Use y = mx + b and the point to find b, the y-intercept
9 = (-2/3)*-5 + b
b = 17/3
--> y = (-2/3)x + 17/3 is the equation

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
First put this equation in the slope intercept form
+2y+-+3x+%2B+5+=+0+
+2y+=+3x+-+5+
+y+=+%283%2F2%29%2Ax+-+5+
Any line perpendicular to this one will have slope =
+-1%2Fm+ where +m+=+3%2F2+
+-1%2Fm+=+-2%2F3+
(-5.9)
Use the point-slope formula
+%28+y+-+9+%29+%2F+%28+x+-%28-5%29+%29+=+-2%2F3+
+%28+y+-+9+%29+%2F+%28+x+%2B+5+%29+=+-2%2F3+
Multiply both sides by +3%2A%28+x+%2B+5+%29+
+3%2A%28+y+-+9+%29+=+-2%2A%28+x+%2B+5+%29+
+3y+-+27+=+-2x+-+10+
+3y+=+-2x+%2B+17+
+y+=+-%282%2F3%29%2Ax+%2B+17%2F3+
check answer:
(-5,9)
+y+=+-%282%2F3%29%2Ax+%2B+17%2F3+
+9+=+-%282%2F3%29%2A%28-5%29+%2B+17%2F3+
+9+=+10%2F3+%2B+17%2F3+
+9+=+27%2F3+
+9+=+9+
OK