Question 727814: x^2+3x/x^2-36 less than or equal to 0
It says solve the inequality
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! It says solve the inequality
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(x^2+3x)/(x^2-36) <= 0
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Factor:
(x(x+3))/[(x-6)(x+6)] <= 0
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Critical value are x = -6,-3,0,6
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Draw a number line and plot those x values
The equality is true for x = 0 and for x = -3
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Test the inequality for a value in each of the 5 intervals defined by those
x values.
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(x(x+3))/[(x-6)(x+6)] <= 0
Test x = -10:: -*-/-*- <= 0 ; false
Test x = -5::: -*-/-*+ <= 0 ; true
Test x = -1::: -*+/-*+ <= 0 ; false
Test x = 3:::: +*+/-*+ <= 0 ; true
Test x = 10::: +*+/+*+ <= 0 ; false
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Solutions: (-6,-3]U[0,6)
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Cheers,
Stan H.
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