SOLUTION: Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x – 5y = 4 and passing through (-3, 5).

Algebra ->  Graphs -> SOLUTION: Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x – 5y = 4 and passing through (-3, 5).      Log On


   

Question 72119: Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x – 5y = 4 and passing through (-3, 5).
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
A LINE PERPENDICULAR TO X-5Y=4 IS IN STANDARD FORM
-5Y=-X+4
Y=X/-5+4/-5
Y=-X/5-4/5 WHICH HAS A SLOPE OF -1/5 SO A PERPENDICULAR LINE'S SLOPE WILL BE 5.
NOW SUBSTITUTE THE X,Y VALUES OF THE POINT AND SOLVE TH STANDARD EQUATON FOR THE Y INTERCEPT(b)
5=5*-3+b
b=5-15
b=-10 SO THE EQUATION OF THIS PERPENDICULAR LINE IS.
Y=5X-10
graph%28300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+-x%2F5+-4%2F5%2C+y+=+5x+-10%29 (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = -x/5 -4/5 and y = 5x -10).