You can put this solution on YOUR website! The intercepts will be when x=0 and you solve for y, and when y=0 and you solve for x. Both situations will give you quadratic equation in one variable.
becomes for whe x=0. Easily factorable to , so intercepts will be at y=2 and y=-12. So see how that works? You can do the same for finding the intercepts when y=0.
Finding radius and center need a different equation form. Put the equation into standard form by Completing the square. Do this for BOTH variables.
Here's getting the process started.
x^2+y^2+10y-24=0
x is already in good shape. No need to complete the square for x. y needs some work.
The square term to add and subtract is . . We now must include that in the original equation:
Putting that result into the original equation, we obtain:
OR