SOLUTION: How do I graph the relation 3y= 9x^2-6x+12?

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Question 706989: How do I graph the relation 3y= 9x^2-6x+12?
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How do I graph the relation 3y= 9x^2-6x+12?
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Pick values for x and find y.
Plot the points, as many as you like.
Draw a curve thru them.
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Reduce it first.
3y= 9x^2-6x+12
y = 3x^2 - 2x + 4

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
graph the relation 3y= 9x^2-6x+12
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Simplify:
y = 3x^2 - 2x +4
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Vertex occurs where x = -b/2a = 2/(6) = 1/3
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f(1/3) = 3(1/9) - (2/3) + 12/3 = 11/3
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Plot the vertex at (1/3 , 11,3)
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y-intercept = f(0) = 4
Plot (0,4)
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Sketch a parabola thru those points opening upward.
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C3x%5E2-2x%2B4%29
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Cheers,
Stan H.
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