SOLUTION: graph the feasible set for the system of inequalities and find the coordinates of the vertices. x+2y> 14 - 2x+y> 16 - x>0,y>0 - - what are the coordinates of th

Algebra ->  Graphs -> SOLUTION: graph the feasible set for the system of inequalities and find the coordinates of the vertices. x+2y> 14 - 2x+y> 16 - x>0,y>0 - - what are the coordinates of th      Log On


   

Question 704294: graph the feasible set for the system of inequalities and find the coordinates of the vertices.
x+2y> 14
-
2x+y> 16
-
x>0,y>0
- -
what are the coordinates of the vertices of the feasable set?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x%2B2y%3E=14
2x%2By%3E=16
x%3E=0
y%3E=0
The boundary lines are the x- and y-axes (y=0 and (x=0 respectively)
and the lines x%2B2y=14 and 2x%2By=16
Those lines intersect at
system%28x%2B2y=14%2C2x%2By=16%29 --> x=6 and y=4 for point (6,4)
The axes intersect at the origin, of course.
The lines intersect the axes at points with x=0 and y=o, and we can find the other coordinate by substituting those zeros.
For x%2B2y=14 we find the intercepts as (0,7) and (14,0)
x=0 --> 2y=14 --> y=7%29%29%29%0D%0A%7B%7B%7By=0 --> x=14
For 2x%2By=16 we find the intercepts as
x=0--> y=16%29%29%29%0D%0A%7B%7B%7By=0 --> 2x=16 --> x=8

GRAPHING:
The feasible set is the quadrilateral OBCD.