SOLUTION: find the x-intercepts nad y-intercepts for the given circle? (x^2)+(y^2)-4x-6y+4=0 ??

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Question 69044This question is from textbook
: find the x-intercepts nad y-intercepts for the given circle?
(x^2)+(y^2)-4x-6y+4=0 ?? This question is from textbook

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%5E2%29%2B%28y%5E2%29-4x-6y%2B4=0First group x's and y's together
%28x%5E2%29-4x%2B%28y%5E2%29-6y=-4Then complete the square
%28x%5E2-4x%2B4%29%2B%28y%5E2-6y%2B9%29=-4%2B4%2B9Simplify
%28x-2%29%5E2%2B%28y-3%29%5E2=9to find x intercept, plug in y=0
%28x-2%29%5E2%2B%280-3%29%5E2=9
%28x-2%29%5E2%2B9=9
sqrt%28%28x-2%29%5E2%29=sqrt%280%29Take square root
%28x-2%29=0
x=2X-intercept is (2,0)
Use same procedure with y-intercept, let x=0
%280-2%29%5E2%2B%28y-3%29%5E2=9
%28-2%29%5E2%2B%28y-3%29%5E2=9
4%2B%28y-3%29%5E2=9
%28y-3%29%5E2=9-4
sqrt%28%28y-3%29%5E2%29=sqrt%285%29take square root of both sides
y-3=0%2B-sqrt%285%29(remember its both positive and negative sqrt%285%29note: ignore the 0 in front of the plus/minus
y=0%2B-sqrt%285%29%2B3
y=5.236+and+0.764of course these are approximate
So the y-intercepts are (0,5.236) and (0,0.764)