SOLUTION: Find an equation of the line tangent to the graph of y=x^2-x+1-ln(x+4) at (-3,13).
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-> SOLUTION: Find an equation of the line tangent to the graph of y=x^2-x+1-ln(x+4) at (-3,13).
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Question 682699
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Find an equation of the line tangent to the graph of y=x^2-x+1-ln(x+4) at (-3,13).
Answer by
solver91311(24713)
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You can
put this solution on YOUR website!
Use the point-slope form
Simplify as required.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it