Question 669204: 13- Show work, graph the function using transformations, state domain, range and asymptotes
F(x)=5- 1/(x+4)²
Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! is related to the functions and .
You know that the function has a graph like this:
.
The x-axis ( ) is a horizontal asymptote that the function approaches as and become larger and larger,
and you know that the function
does not exist for because you cannot divide by zero.
Instead, you have a vertical asymptote at ,
and there is no limit to the values can take.
It is never zero, but can take any other value.
Something similar happens with the function ,
which does not exist for and graphs as 
The only difference is that is never negative.
The domain is all real numbers except zero; the range is all , and the asymptotes are the same.
The function is like ,
but everything is shifted 4 units to the left.
What happened to for , , and 
now happens for at , , and .
The graph for is .
The vertical asymptote is .
(All other real numbers are in the domain of ).
Adding a minus sign in front just flips the graph.
Everything becomes the reflection under the x-axis:

Adding to that, just moves the graph (and asymptotes) up by 5 units.

The domain is all the real numbers except .
The vertical asymptote is .
The range is all .
The horizontal asymptote (shown in green) is .
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