SOLUTION: Find the equation of a line perpendicular to 2x-5y=10 passes through the points (3,-1)

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Question 668181: Find the equation of a line perpendicular to 2x-5y=10 passes through the points (3,-1)
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular lines have a negative inverse slope.
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Using 2x -5y = 10 rewritten as y = %282%2F5%29x+-+2
The slope is 2%2F5
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The slope of the perpendicular line will be -5%2F2
Using this slope and the point (3, -1), solve for y-intercept, b.
-1 = -5%2F23 + b
Isolate b
b = -1 + 15%2F3 = -3%2F3+%2B+15%2F3+=+12%2F3+=+4
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The linear equation of the perpendicular line is
highlight%28y=-%285%2F2%29x+%2B+4%29
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Red line: y = -5%2F2x + 4
Green line: y = %282%2F5%29x+-+2
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graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C+%28-5%2F2%29x%2B4%2C+%282%2F5%29x-2%29
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