SOLUTION: I really need help with this problem: Graph {{{ y= sqrt ( x+2 )}}} and give the domain and range. I figured out the domain and range. Domain- [-2,positive infinity) Range- [0

Algebra ->  Graphs -> SOLUTION: I really need help with this problem: Graph {{{ y= sqrt ( x+2 )}}} and give the domain and range. I figured out the domain and range. Domain- [-2,positive infinity) Range- [0      Log On


   

Question 660836: I really need help with this problem:
Graph +y=+sqrt+%28+x%2B2+%29 and give the domain and range.
I figured out the domain and range.
Domain- [-2,positive infinity)
Range- [0, positive infinity)
I just don't know how to graph it.
I would greatly appreciate it if someone could help me out.
Thank you.
Found 2 solutions by MathLover1, math-vortex:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

make a table first, find several points (x,y), plot them on Cartesian coordinate system and draw a graph
x|y
0|1%2C41.......+y=+sqrt+%28+0%2B2+%29..+y=+sqrt+%28+2+%29=1.41
-1|1.....+y=+sqrt+%28+-1%2B2+%29..+y=+sqrt+%28+1+%29=1
-2|0.....+y=+sqrt+%28+-2%2B2+%29..+y=+sqrt+%28+0+%29=0
2|2.....+y=+sqrt+%28+2%2B2+%29..+y=+sqrt+%28+4+%29=2
7|3.....+y=+sqrt+%28+7%2B2+%29..+y=+sqrt+%28+9+%29=3
14|4.....+y=+sqrt+%28+14%2B2+%29..+y=+sqrt+%28+16+%29=4
it should look like this:
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C++sqrt+%28+x%2B2+%29%29+

Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!

Hi, there--

Problem:
Graph y=sqrt%28x%2B2%29 and give the domain and range.

Answer:
Your domain and range are correct.

The graph of y=sqrt%28x%2B2%29 looks exactly like the graph of y=sqrt%28x%29 except it is shifted 2 units to the left.

The graph looks a little like a half a parabola laying on its side (opening to the right.) The 
graph of your equation intersects the x-axis at (-2,0).

To get a sketch of the graph, make a quick (x,y) table:

x      y
-2    0
-1    1
2      2
7      3
14    4

Remember that x≥2, and y≥0.

You can see a picture of the graph if you google "graph y=sqrt(x+2)" (Don't include quotation 
marks.)

Hope this helps! Feel free to email, if you still have questions.

Mrs.Figgy