SOLUTION: How would I graph the system of inequalities y<2x-1 x+y>=2

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Question 657547: How would I graph the system of inequalities y<2x-1
x+y>=2

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Since there is an x and a y in your system, you need an x-axis and a y-axis in your graph.
Each inequality will be represented as the half of the x-y plane to one side of a boundary line.

The equation x%2By=2 represents one of those boundary lines, and is graphed as a solid line, because all the points on that line are part of the solution to
x%2By%3E=2. Any point (x,y) in that line satisfies x%2By=2 and also satisfies x%2By%3E=2.
graph%28300%2C300%2C-2%2C8%2C-2%2C8%2C2-x%29 is the graph (line) for x%2By=2, and the inequality x%2By%3E=2 graphs as graph%28300%2C300%2C-2%2C8%2C-2%2C8%2C2-x%2Cx%2By%3E=2%29

The equation y=2x-1 represents the boundary line for y%3C2x-1, and is graphed as a dashed line, because the points (x,y) with y=2x-1 do not satisfy y%3C2x-1

To graph each line you need 2 points.
To get a point you chose a value for x and find the corresponding y or the other way around. A value of zero is often a good choice.

FOR x%2By=2:
x=0 gives you 0%2By=2 --> y=2 for the point (0,2).
y=0 gives you x%2B0=2 --> x=2 for the point (2,0).
You plot the two points and connect them with a line to graph x%2By=2


FOR x%2By%3E=2:
You graph the line as shown above. It is a solid line because there is a "=" in the inequality, and that causes the solutions to x%2By=2 to be solutions of x%2By%3E=2.
Next, you figure out which side of the line to shade or color.
An easy way to do it is to pick a point on one side of the line and check if it is part of the solution.
The easiest choice (if not on the line) is the point (0,0), with x=y=0
For that point x%2By=0%2B0%3C2, so that point is not part of the solution.

FOR y%3C2x-1:
You plot the line for y=2x-1 as a dashed line, because it is not part of the solution.
x=0 gives you y=2%2A0-1--> y=-1 for point (0,-1).
Choosing y=0 would not make the calculations or the graphing easy, so I pick x=3 for the second point.
x=3 gives me y=2%2A3-1 --> y=5 for point (3,5).
I plot the points and connect them with a dashed line:
Finally, I decide which side of the line is the solution to y%3C2x-1.
Using (0,0), the origin, as a test point, I figure that the solution is the side that does not contain the origin,
because substituting x=y=0 into y%3C2x-1, I get
0%3C2%2A0-1=-1, which is not true.
The colored graph of the inequality will look like this:
graph%28300%2C300%2C-2%2C8%2C-2%2C8%2Cy%3C2x-1%29

The solution to the system is the part of the x-y plane that is a solution to both inequalities. It graphs as the colored or shaded pie wedge bounded by the lines, as shown below.