SOLUTION: what is the equation of a line passing through (-2, -1) and (6, 3)?

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Question 655963: what is the equation of a line passing through (-2, -1) and (6, 3)?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-2, -1) and (x2, y2) = (6, 3).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%283--1%29%2F%286--2%29+=+0.5.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 0.5%2A-2+%2Bb+=+0. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-1-0.5%2A-2+=+0.

y=(0.5)x + (0)

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