SOLUTION: I am trying to test an equation for symmetry. The equation is x^2 = y^3 + 4.
I am starting by trying to find the intercepts. I think I found the intercepts for x - (2,0), (-2,
Algebra ->
Graphs
-> SOLUTION: I am trying to test an equation for symmetry. The equation is x^2 = y^3 + 4.
I am starting by trying to find the intercepts. I think I found the intercepts for x - (2,0), (-2,
Log On
Question 643877: I am trying to test an equation for symmetry. The equation is x^2 = y^3 + 4.
I am starting by trying to find the intercepts. I think I found the intercepts for x - (2,0), (-2,0). I am having trouble finding the intercepts for y.
I substitute 0 for X and get 0 + y^3 + 4. I convert that to y^3 = -4. I am not sure where to go from there. Can I get a cube root of four? Solving for y, would my answer be the cube root of four i? Does that mean there is no y intercept?
I've confused myself... Thanks for any help. Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!
I am trying to test an equation for symmetry. The equation is x^2 = y^3 + 4.
I am starting by trying to find the intercepts. I think I found the intercepts for x - (2,0), (-2,0). I am having trouble finding the intercepts for y.
I substitute 0 for X and get 0 + y^3 + 4. I convert that to y^3 = -4. I am not sure where to go from there. Can I get a cube root of four? Solving for y, would my answer be the cube root of four i? Does that mean there is no y intercept?
I've confused myself... Thanks for any help.
y-intercept = , or - 1.587401052 ≈
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com