SOLUTION: y=x^2+3 Give the coordinates of the x intercepts (if they exits) for the graph of each equation. in simplest form thanks so much for your help in advance!

Algebra ->  Graphs -> SOLUTION: y=x^2+3 Give the coordinates of the x intercepts (if they exits) for the graph of each equation. in simplest form thanks so much for your help in advance!      Log On


   

Question 642800: y=x^2+3
Give the coordinates of the x intercepts (if they exits) for the graph of each equation. in simplest form thanks so much for your help in advance!
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
Answer: NO x-intercept
Solution:
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B0x%2B3+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%280%29%5E2-4%2A1%2A3=-12.

The discriminant -12 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -12 is + or - sqrt%28+12%29+=+3.46410161513775.

The solution is

Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B0%2Ax%2B3+%29