SOLUTION: y=x^2-2x Give the coordinates of the x intercepts (if they exits) for the graph of each equation. in simplest form thanks so much for your help in advance!

Algebra ->  Graphs -> SOLUTION: y=x^2-2x Give the coordinates of the x intercepts (if they exits) for the graph of each equation. in simplest form thanks so much for your help in advance!      Log On


   

Question 642799: y=x^2-2x
Give the coordinates of the x intercepts (if they exits) for the graph of each equation. in simplest form thanks so much for your help in advance!
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
Answers: (0,0),(2,0)
Solution:
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-2x%2B0+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-2%29%5E2-4%2A1%2A0=4.

Discriminant d=4 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--2%2B-sqrt%28+4+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-2%29%2Bsqrt%28+4+%29%29%2F2%5C1+=+2
x%5B2%5D+=+%28-%28-2%29-sqrt%28+4+%29%29%2F2%5C1+=+0

Quadratic expression 1x%5E2%2B-2x%2B0 can be factored:
1x%5E2%2B-2x%2B0+=+1%28x-2%29%2A%28x-0%29
Again, the answer is: 2, 0. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-2%2Ax%2B0+%29