SOLUTION: find vertex of x^2-6x+6

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Question 613756: find vertex of x^2-6x+6
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Parabola opening Up (coefficient of the x^2 term > 0)

 y = x^2-6x+6 = (x-3)^2 -9  +6 = (x-3)^2 - 3   Vertex(3,-3)