SOLUTION: Solve this system of linear equations: {{{5x+2y=-10}}} {{{y+3=0}}}

Algebra ->  Graphs -> SOLUTION: Solve this system of linear equations: {{{5x+2y=-10}}} {{{y+3=0}}}      Log On


   

Question 596753: Solve this system of linear equations:
5x%2B2y=-10
y%2B3=0
Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, there--
.
We can use solve this system using the substitution method.
.
Rewrite the second equation in terms of y.
y%2B3=0
y=-3
.
Substitute -3 for y in the first equation.
5x%2B2y=-10
5x%2B2%28-3%29=-10
.
Simplify the equation and solve for x.
5x%2B%28-6%29=-10
5x-6=-10
.
Add 6 to both sides of the equation.
5x=-4
.
Divide both sides by 5.
x=-%284%2F5%29
.
The solution for this system is the ordered pair (-4/5, -3).
.
CHECK your work by substituting this ordered pair into both equations.
5x%2B2y=-10
5%28-%284%2F5%29%29%2B2%28-3%29=-10
%28-4%29%2B%28-6%29=-10
-10=-10
Bingo!
.
y%2B3=0
There is no x-term in this equation, so we only substitute the y-value.
%28-3%29%2B3=0
0=0
Perfect!
.
That's it. Feel free to email if this explanation is unclear.
.
Ms.Figgy
math.in.the.vortex@gmail.com