SOLUTION: okay for the function y=1 over x-2 it says to give the y values for x= -2, -1,0 1,2,3 okay i got y= -4,-3,-2,-1,0,1 i plotted tem and i got a line it says using these points draw a

Algebra ->  Graphs -> SOLUTION: okay for the function y=1 over x-2 it says to give the y values for x= -2, -1,0 1,2,3 okay i got y= -4,-3,-2,-1,0,1 i plotted tem and i got a line it says using these points draw a      Log On


   

Question 58637: okay for the function y=1 over x-2 it says to give the y values for x= -2, -1,0 1,2,3 okay i got y= -4,-3,-2,-1,0,1 i plotted tem and i got a line it says using these points draw a curve i got a line did i do something wrong or am i not just understanding the question any help please
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
y=1%2F%28x-2%29 give the y values for x= -2, -1,0 1,2,3
If x=-2
y=1%2F%28-2-2%29=-1%2F4
If x=-1
y=1%2F%28-1-2%29=-1%2F3
If x=0
y=1%2F%280-2%29=-1%2F2
If x=1
y=1%2F%281-2%29=-1
If x=2
y=1%2F%282-2%29=1%2F0
*When there's a 0 in the denominator the fraction is undefined. x cannot=2, there is a vertical asymptote of x=2.
If x=3
y=1%2F%283-2%29=1
This gives you a graph like this. The program draws in the vertical asymtote at x=2. This is not actually part of the graph and when you graph this you may put a vertical dashed line in at x=2.
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C1%2F%28x-2%29%29
Happy Calculating!!!