SOLUTION: write a rule for linear functions with graphs containing the foollowing pairs of points. (-6,4) and (3,-8)

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Question 559671: write a rule for linear functions with graphs containing the foollowing pairs of points.
(-6,4) and (3,-8)
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You could write the rule in the form of a "slope-intercept" linear equation: y+=+mx%2Bb by finding the slope;
m+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Use the x- and y-coordinates of the two given points (-6, 4) and (3, -8) as the inputs.
m+=+%28-8-4%29%2F%283-%28-6%29%29
m+=+%28-12%29%2F9
m+=+-4%2F3 so you have:
y+=+%28-4%2F3%29x%2Bb To find b, substitute the x- and y-coordintes from either one of the given points. Say (3, -8).
-8+=+%28-4%2F3%29%2A3%2Bb
-8+=+-4%2Bb Add 4 to both sides.
-4+=+b now you write the finished equation (rule):
y+=+%28-4%2F3%29x-4